Column I | Column II (Hydrolysis product) | |
[a] | \[Xe{{F}_{2}}\] | (p) HF |
[b] | \[Xe{{F}_{4}}\] | (q) \[Xe{{O}_{3}}\] |
[c] | \[Xe{{F}_{6}}\] | (r) \[Xe\] |
(s) Show disproportion |
A)
A - p, r B - q, r C - r, s
B)
A - q, r B - q, r, s C - q
C)
A - r B - s C - p , q, r, s
D)
A - p ,r B - p, q, r, s C - q
Correct Answer: D
Solution :
\[2Xe{{F}_{2}}+2{{H}_{2}}O\xrightarrow{\,}\,2Xe+4HF+{{O}_{2}}\] \[6Xe{{F}_{4}}+12{{H}_{2}}O\,\xrightarrow{\,}\,2Xe{{O}_{3}}+4Xe\,+3{{O}_{2}}+HF\] \[Xe{{F}_{6}}\,+3{{H}_{2}}O\xrightarrow{\,}Xe{{O}_{3}}+6HF\]You need to login to perform this action.
You will be redirected in
3 sec