A) \[{{O}_{2}}\] at anode and \[{{H}_{2}}\] at cathode
B) \[{{H}_{2}}\] at anode and Zn at cathode
C) \[{{O}_{2}}\] at anode and Zn at cathode
D) \[{{H}_{2}}{{S}_{2}}{{O}_{8}}\] at anode and \[{{H}_{3}}\] at cathode
Correct Answer: A
Solution :
at anode \[2{{H}_{2}}O\xrightarrow{\,}\,O_{2}^{+}\,+4{{H}^{+}}\,+4{{e}^{-}}\] at cathode \[2{{H}^{+}}+2{{e}^{-}}\xrightarrow{\,}\,{{H}_{2}}\] (Acidic Solution)
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