A) 24 lit. of HCl (g)
B) \[0.8\] litre \[C{{l}_{2}}\], and \[20.8\] lit. HCl (g)
C) \[0.8\] lit. \[{{H}_{2}}\] and \[22.4\] lit. HCl (g)
D) \[22.4\] lit. HCl (g)
Correct Answer: C
Solution :
\[{{H}_{2}}\,\,\,\,\,\,\,\,\,\,+\,\,\,\,\,\,\,\,\,\,\,C{{l}_{2}}\xrightarrow{\,}\,\,\,\,\,\,\,2HCl\] \[12lit\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,11.2lit\] \[0.8\,lit\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,L.R\] So, \[HCl\] will be double i.e. 22.4 lit. So. 0.8 lit. \[{{H}_{2}}\] and 22.4 lit. \[HCl(g)\] (mixture).You need to login to perform this action.
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