| (i) Tollen's reagent |
| (ii) \[{{I}_{2}}\]/NaOH |
| (iii) Lucas reagent |
| (iv) neutral \[FeC{{l}_{3}}\] |
A) (i), (ii) & (iii)
B) (ii) & (iii)
C) (i) & (ii)
D) (iii) & (iv)
Correct Answer: C
Solution :
Acetaldehyde and Propyne can be distinguish by toiler's reagent and lodo form test.
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