A) 1
B) 2
C) 4
D) 5
Correct Answer: D
Solution :
Plane P passes through (1, 5, 3) and normal to \[\vec{A}=(2,3,6)\] Equation is \[2(x-1)+3(y-5)\,+6(z-3)\,=0\]\[\Rightarrow \,2x+3y+6z=35\] \[\therefore \] Perpendicular from (0, 0, 0) to the plane \[=\left| \frac{-35}{7} \right|=5\]You need to login to perform this action.
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