A) 10
B) 9
C) 8
D) 5
Correct Answer: B
Solution :
Let \[\vec{V}\] is the vector along the line of intersection of the planes \[2x-y-3z-8=0\] and \[x+2y-4z-14=0\] then \[V=\left| \begin{matrix} {\hat{i}} & {\hat{j}} & {\hat{k}} \\ 2 & -1 & -3 \\ 1 & 2 & -4 \\ \end{matrix} \right|\,=5(\hat{i}+\hat{j}+\hat{k})\] This is \[\bot \] to join of (a, 2, 2) and (6, 11, -1). Vector \[{{\vec{V}}_{1}}\] along this is, \[{{\vec{V}}_{1}}=(a-6)\hat{i}-9\hat{j}+3\hat{k}\] Now, \[\vec{V}.\,{{\vec{V}}_{1}}=0\] gives a = 9.You need to login to perform this action.
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