A) 1
B) 2
C) 3
D) 4
Correct Answer: B
Solution :
Vector normal to the plane is \[\vec{n}=\hat{i}-3\hat{j}+2\hat{k}\] and vector along the line is \[\vec{V}=2\hat{i}+\hat{j}-3\hat{k}\] Now \[\sin \theta =\frac{n.v}{|n||v|}\,=\left| \frac{2-3-6}{\sqrt{14}\,\sqrt{14}} \right|\,=\left| \frac{7}{14} \right|\] Hence \[\cos ec\,\theta =2\]You need to login to perform this action.
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