• # question_answer The particle A is converted into C via following reaction. $A\to B{{+}_{2}}H{{e}^{4}}$ $B\to C+2{{e}^{-}}$ Then, A)  A and C are isobars        B)  A and C are isotopes C)  A and B are isobars D)  A and B are isotopes

Solution :

Let x be the mass number of A and y be the atomic number. Since atomic number and mass number remain conserved, we have $_{y}{{A}^{x}}{{\to }_{y-2}}{{B}^{x-4}}\,{{+}_{2}}H{{e}^{4}}$ $_{y-2}{{B}^{x-4}}{{\to }_{y}}{{B}^{x-4}}\,+{{2}_{-1}}{{e}^{0}}$ Hence, we observe that A and C are isotopes as their atomic numbers are same but mass numbers are different.

You need to login to perform this action.
You will be redirected in 3 sec