A) \[31.4\] N-m
B) \[3.14\] N-m.
C) \[0.314\] N-m
D) zero
Correct Answer: D
Solution :
Torque (T) acting on a loop placed in a magnetic field B is given by \[\tau \,=nBIA\,\sin \theta \]where, A is area of loop, I the current through it, n the number of turns, and \[\theta \] the angle which axis of loop makes with magnetic field B. Since, magnetic field is parallel to the axis of the coil hence \[\theta =0{}^\circ \] and s\[\sin {{0}^{0}}=0\]\[\tau \,=0\]You need to login to perform this action.
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