A) 8
B) 7
C) 9
D) 11
Correct Answer: A
Solution :
We know that angular momentum is given by \[L=I\omega \] \[{{I}_{1}}{{\omega }_{1}}={{I}_{2}}{{\omega }_{2}}\] Disc = R, R Ring = m, r Then \[{{\omega }_{2}}=\left( \frac{{{I}_{1}}}{{{I}_{2}}} \right){{\omega }_{1}}=\left[ \frac{\frac{1}{2}\,M{{R}^{2}}}{\frac{1}{2}\,M{{R}^{2}}+2(2m{{r}^{2}})} \right]\,{{\omega }_{1}}\] \[=\left[ \frac{50{{(0.4)}^{2}}}{50{{(0.4)}^{2}}+8\times (6.25)\,\times {{(0.2)}^{2}}} \right]\,(10)\] \[=8rad/s\]You need to login to perform this action.
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