A) \[0.1\]
B) 10
C) \[1.5\]
D) \[1.0\]
Correct Answer: D
Solution :
For given buffer solution pH,=pKa Now 9 mL of 1 M HCl is added to (10 + x) mL of this solution \[NaA\,\,\,\,\,+\,\,\,\,\,HCl\,\xrightarrow{\,}\,\,\,HA\,\,\,\,\,+\,\,\,NaCl\] \[1\times (10+x)\,\] \[(1\times 9)\] \[1(10+x)\,\,\,\,0\] \[(10+x)-9\,\,\,0\] \[(10+x)\,+9\] \[p{{H}_{1}}-p{{H}_{2}}=1\] \[\log \,\frac{(10+x)-9}{(10+x)\,+9}=\frac{1}{10}\] \[\frac{(10+x)\,-9}{(10+x)\,+9}=\frac{1}{10}\] \[x=1\,\,ml\].You need to login to perform this action.
You will be redirected in
3 sec