A) \[-0.245\] J
B) \[-2.45\times {{10}^{-4}}\] J
C) \[-0.0245\] J
D) \[-24.5\times {{10}^{-4}}\] J
Correct Answer: D
Solution :
Torque \[\tau \,=pE\,\sin \theta \,\Rightarrow \,P=\frac{\tau }{E\sin \theta }\]Potential energy \[U=-pE\cos \theta \,=\frac{-\tau }{E\,\sin \,\theta }.\,E\cos \theta \] \[=\frac{-\tau }{E\sin \theta }\,=\frac{-10\sqrt{2}}{{{10}^{4}}\,\tan {{30}^{0}}}\,=-24.5\times {{10}^{-4}}J\]You need to login to perform this action.
You will be redirected in
3 sec