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JEE Main & Advanced Sample Paper JEE Main Sample Paper-26

  • question_answer
    A long cylindrical tube carries a highly polished piston and has a side opening. A tunning fork of frequency v is sounded at the sound heard by the listener changes if the piston is moved in or out. At a particular position of the piston is moved through a distance of 9 cm, the intensity of sound becomes minimum, if the speed of sound is 360 m/s, the value of v is:

    A)  129.6 Hz                     

    B)  500 Hz

    C)  1000 Hz                      

    D) 2000 Hz

    Correct Answer: C

    Solution :

    When piston moves a distance x^, path difference change by 2x. \[\therefore \] The path difference between maxima and consecutive minima = \[\lambda /2\] \[2x=\lambda /2\] or \[\lambda =4xf\,=4\times 9\,\,cm\,=36\,cm\,=0.36\,cm\] \[v=\frac{v}{\lambda }=\frac{360}{0.36}\,=1000\,Hz\]


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