A) \[{{H}_{3}}B{{O}_{3}}\xrightarrow{{{H}_{2}}O}{{H}_{3}}^{+}O+{{H}_{2}}BO_{3}^{-}\]
B) \[{{H}_{3}}B{{O}_{3}}\xrightarrow{2{{H}_{2}}O}2H_{3}^{+}O+{{H}_{2}}BO_{3}^{2-}\]
C) \[{{H}_{3}}B{{O}_{3}}\xrightarrow{3{{H}_{2}}O}3H_{3}^{+}O+{{H}_{2}}BO_{3}^{3-}\]
D) \[{{H}_{3}}B{{O}_{3}}\xrightarrow{{{H}_{2}}O}B(OH)_{4}^{+}+{{H}^{+}}\]
Correct Answer: D
Solution :
\[{{H}_{3}}B{{O}_{3}}\] is weak, Lewis monobasic acid and shows the given equilibrium. \[{{H}_{3}}B{{O}_{3}}+{{H}_{2}}O\rightleftharpoons \,B(OH)_{4}^{-}\,+{{H}^{+}}\]
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