• # question_answer Unlike $PbC\,{{l}_{4}},\,\,P{{I}_{4}}$ and $PB{{r}_{4}}$ are not found because: A)  chlorine is more electropositive. B)  iodine and bromine are of large size. C)  iodine and bromine are unable to oxidise Pb to $P{{b}^{4+}}$ D)  The statement is wrong.

Iodine and bromine are unable to oxidize Pb to $P{{b}^{4+}}$ On account of inert pair effect the stable oxidation state of Pb is +2. So $P{{b}^{4+}}$ acts as oxidising agent and oxidises ${{I}^{-}}$ and $B{{r}^{-}}$ to ${{I}_{2}}$ and $B{{r}_{2}}$ respectively and itself reduced to