Compound X in the above reaction is:
A)
B)
C)
D)
Correct Answer: B
Solution :
\[Ph-\overset{\begin{smallmatrix} \,\,\,\,\,C{{H}_{3}} \\ \,\,\,\,\,\,\,\,|\,\, \end{smallmatrix}}{\mathop{C}}\,=CH-Ph\xrightarrow{{{O}_{3}}/Zn}\,Ph-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{3}}+PH-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{C}}\,-H\] \[\xrightarrow{{}}\,Ph-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{2}}-\underset{\begin{smallmatrix} \,| \\ {{O}^{\oplus }} \end{smallmatrix}}{\mathop{C}}\,H-Ph\,\xrightarrow{{{H}^{\oplus }}}\] \[Ph-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{C}}\,-C{{H}_{2}}-\underset{\begin{smallmatrix} \,\,\,\,| \\ OH \end{smallmatrix}}{\mathop{C}}\,H-Ph\xrightarrow{\,}\,Ph-\underset{\begin{smallmatrix} \,|| \\ O \end{smallmatrix}}{\mathop{C}}\,\,-CH\,=CH-Ph\]82
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