A) \[Ph-C{{H}_{2}}-C{{H}_{2}}-C{{H}_{2}}-OH\]
B) \[Ph-\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}\]
C) \[Ph-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{C}}\,}}\,-\overset{\begin{smallmatrix} H \\ | \end{smallmatrix}}{\mathop{\underset{\begin{smallmatrix} | \\ H \end{smallmatrix}}{\mathop{C}}\,}}\,-C{{H}_{3}}\]
D) \[Ph-C{{H}_{2}}-OH\]
Correct Answer: C
Solution :
\[Ph-C{{H}_{2}}-\overset{\oplus }{\mathop{C}}\,H-C{{H}_{3}}\,\xrightarrow{1,2{{H}^{-}}\,shift}\] \[Ph-\overset{\oplus }{\mathop{C}}\,H-C{{H}_{2}}-C{{H}_{3}}\,\xrightarrow{{{H}_{2}}\overset{\begin{smallmatrix} .\,\,. \\ .\,\,. \end{smallmatrix}}{\mathop{O}}\,:}\] \[Ph-\underset{\begin{smallmatrix} | \\ OH \end{smallmatrix}}{\mathop{CH}}\,-C{{H}_{2}}-C{{H}_{3}}\]
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