A) \[\frac{1}{2}(1-\ell n2)\]
B) \[\frac{1}{2}\left( \ell n2+\frac{1}{2} \right)\]
C) \[\frac{1}{2}(1+\ell n2)\]
D) \[\frac{1}{2}\left( \ell n2-\frac{1}{2} \right)\]
Correct Answer: D
Solution :
Area \[=\int\limits_{0}^{\frac{\pi }{4}}{(\tan x)dx-\frac{1}{2}\left( \frac{1}{2} \right)\,(1)=\frac{1}{2}\,\left( \ell n2-\frac{1}{2} \right)}\]You need to login to perform this action.
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