A) \[\left( \frac{{{I}_{0}}}{8} \right){{\sin }^{2}}(2\theta )\]
B) \[\left( \frac{{{I}_{0}}}{4} \right){{\sin }^{2}}(2\theta )\]
C) \[\left( \frac{{{I}_{0}}}{2} \right){{\cos }^{4}}(\theta )\]
D) \[{{I}_{0}}{{\cos }^{4}}(\theta )\]
Correct Answer: A
Solution :
Let initial intensity of light is \[{{I}_{0}}\] so, intensity of light after transmission from first polaroid \[=\frac{{{I}_{0}}}{2}\] Intensity of light emitted from \[{{P}_{3}}\] \[{{I}_{1}}=\frac{{{I}_{0}}}{2}\,{{\cos }^{2}}\theta \] Intensity of light transmitted from last polarized \[{{P}_{2}}={{I}_{1}}{{\cos }^{2}}\,({{90}^{0}}-\theta )\] \[{{P}_{2}}=\frac{{{I}_{0}}}{2}\,{{\cos }^{2}}\theta \,{{\sin }^{2}}\theta \] \[{{P}_{2}}=\frac{{{I}_{0}}}{8}\,{{(2\sin \theta \,\cos \theta )}^{2}}\] \[{{P}_{2}}=\frac{{{I}_{0}}}{8}\,{{\sin }^{2}}2\theta \]You need to login to perform this action.
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