A) \[nE/(n+1)\]
B) \[(n+1)E/n\]
C) E
D) \[E/n\]
Correct Answer: A
Solution :
Maximum elastic potential energy\[=\frac{1}{2}\,\mu U_{res}^{2}\] \[=\frac{1}{2}\,\frac{{{m}_{1}}{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}}\,{{({{U}_{1}}-{{U}_{2}})}^{2}}=\frac{1}{2}\,\frac{m\,nm}{m+nm}\,{{(U-0)}^{2}}\] \[=\frac{1}{2}\,m{{U}^{2}}\left( \frac{n}{1+n} \right)=\frac{En}{1+n}\]You need to login to perform this action.
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