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JEE Main & Advanced Sample Paper JEE Main Sample Paper-27

  • question_answer
    The equilibrium constants for the reaction\[S{{O}_{3(g)}}S{{O}_{2(g)}}+\frac{1}{2}{{O}_{2}}(g)\]  &\[2S{{O}_{2(g)}}+{{O}_{2(g)}}2S{{O}_{3(g)}}\] are \[{{K}_{1}}\] & \[{{K}_{2}}\] respectively. The relation between \[{{K}_{1}}\] & \[{{K}_{2}}\] is

    A)  \[{{K}_{1}}=\sqrt{{{K}_{2}}}\]          

    B)  \[{{K}_{1}}=\frac{1}{\sqrt{{{K}_{2}}}}\]

    C)  \[{{K}_{1}}=\frac{1}{K_{2}^{2}}\]               

    D)  \[{{K}_{1}}=\frac{1}{\sqrt{{{K}_{2}}}}\]

    Correct Answer: D

    Solution :

    \[{{K}_{1}}=\frac{[S{{O}_{2}}]{{[{{O}_{2}}]}^{1/2}}}{[S{{O}_{3}}]}\,,\,\,{{K}_{2}}=\frac{[S{{O}_{3}}]}{[S{{O}_{2}}]\,[{{O}_{2}}]}\] \[\therefore \,\,\,K_{1}^{2}\,=\frac{1}{{{K}_{2}}}\,\,\,\,\,\,\,\,\,\,\,{{K}_{1}}=\frac{1}{\sqrt{{{K}_{2}}}}\]


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