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JEE Main & Advanced Sample Paper JEE Main Sample Paper-27

  • question_answer
    The observed dipole moment is \[1.03\text{ }D\] and their intern clear distance is \[1.275\overset{{}^\circ }{\mathop{A}}\,\] (\[ID={{10}^{-18}}\]esu.cm). The % covalent character in \[H-Cl\]bond is present

    A)  \[17%\]                        

    B)  \[83%\]

    C)  \[20%\]                        

    D)  \[80%\]

    Correct Answer: B

    Solution :

    % Ionic character \[=\frac{{{\mu }_{observed}}}{{{\mu }_{calulated}}}\,\times 100\] \[\overset{s+}{\mathop{H}}\,-\overset{s-}{\mathop{Cl}}\,\] \[\delta =4.8\times {{10}^{-10}}\,esu\] \[d=1.275\,\times {{10}^{-8}}cm\] \[=\frac{1.03\times 100}{4.8\,\times {{10}^{-10}}\,\times 1.275\,\times {{10}^{-8}}\,(cm)}\] \[=\frac{1.03(D)\times 100}{4.8\times 1.275\,\times {{10}^{-18}}\,(esu.\,cm)}\] \[=\frac{1.03\,(D)}{4.8\times 1.275(D)}\,\times 100\,=\,16.8\,=17%\] \[\therefore \,\,%\] Covalent character = 100 - % Ionic character = 100 - 17 %  = 83%


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