A) \[33.33%\]
B) \[66.67%\]
C) \[50%\]
D) \[25%\]
Correct Answer: B
Solution :
\[\frac{{{a}_{1}}{{m}_{1}}\,+{{a}_{2}}{{m}_{2}}}{{{m}_{1}}+{{m}_{2}}}\,=200\] \[{{a}_{1}}:\] mass of I isotope \[{{m}_{1}}:\] :% of I isotope \[{{a}_{2}}:\] mass of II isotope \[{{m}_{2}}:\] % of ll isotope \[\frac{201x+198(100-x)}{x+(100-x)}\,=200\] \[\frac{201x+19800-198x}{100}=200\] \[x=66.67%\]You need to login to perform this action.
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