A) \[NO<{{C}_{2}}<{{O}_{2}}^{-}<{{B}_{2}}\]
B) \[{{B}_{2}}<{{O}_{2}}^{-}<NO<{{C}_{2}}\]
C) \[{{C}_{2}}<NO<{{B}_{2}}<{{O}_{2}}^{-}\]
D) \[{{B}_{2}}<{{O}_{2}}^{-}<{{C}_{2}}<NO\]
Correct Answer: D
Solution :
\[{{B}_{2}}\] bond order \[=\frac{6-4}{2}\,=1;\] \[O_{2}^{-}\] bond order \[=\frac{10-7}{2}=1.5\] \[{{C}_{2}}\] bond order \[=\frac{8-4}{2}=2;\] NO bond order \[=\frac{10-5}{2}=2.5\]
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