A) 2
B) 1
C) 0
D) 3
Correct Answer: D
Solution :
\[\underset{x\to 2}{\mathop{Lim}}\,\,\frac{\tan (x-2)\,.({{x}^{2}}+(k-2)(x-2k)}{({{x}^{2}}-4x+4)}=4\] \[\left( \frac{0}{0} \right)\] \[\Rightarrow \,\,k+2=5\] \[\Rightarrow \,\,k=3\]You need to login to perform this action.
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