A) 1
B) 3
C) 4
D) 2
Correct Answer: D
Solution :
velocity of first bob at highest point,\[{{v}_{1}}=\sqrt{gR}\,=\sqrt{g{{l}_{1}}}\] (to just complete the vertical circle) velocity of first bob just before elastic collision = velocity of second bob at the bottom most point \[=\sqrt{2g{{l}_{2}}}\]\[\Rightarrow \,\,\frac{{{l}_{1}}}{{{l}_{2}}}=2\]You need to login to perform this action.
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