question_answer

To get 2,4,6 tribromo benzoic acid from aniline the correct sequence of reagents is :

A)  \[\xrightarrow[{{H}_{2}}O]{B{{r}_{2}}}\xrightarrow[{{H}_{2}}O]{{{H}_{3}}{{O}^{\oplus }}}\xrightarrow[(ii)\,CuCN]{(i)\,NaN{{O}_{2}}/HCl}\]

B)  \[\xrightarrow[\Delta ]{{{H}_{3}}{{O}^{\oplus }}/{{H}_{2}}O}\xrightarrow[{{H}_{2}}O]{B{{r}_{2}}}\xrightarrow[(ii)\,CuCN]{(i)\,NaN{{O}_{2}}/HCl}\]

C)  \[\xrightarrow[(ii)\,CuCN]{(i)\,NaN{{O}_{2}}/HCl}\xrightarrow[\Delta ]{{{H}_{3}}{{O}^{\oplus }}/{{H}_{2}}O}\xrightarrow[{{H}_{2}}O]{B{{r}_{2}}}\]

D)  \[\xrightarrow[{{H}_{2}}O]{B{{r}_{2}}}\xrightarrow[(ii)\,CuCN]{(i)\,NaN{{O}_{2}}/HCl}\xrightarrow[\Delta ]{{{H}_{3}}{{O}^{\oplus }}/{{H}_{2}}O}\]

Correct Answer: D

Solution :