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JEE Main & Advanced Sample Paper JEE Main Sample Paper-28

  • question_answer
    If the area bounded by the parabolas \[{{y}^{2}}=4\alpha (x+\alpha )\] and \[{{y}^{2}}=-4\alpha (x-\alpha )\], where \[\alpha >0\] is 48 square units then \[\alpha \] is equal to

    A)  \[\frac{1}{3}\]                                                  

    B)  \[\frac{1}{9}\]

    C)  3                                            

    D)  9

    Correct Answer: C

    Solution :

    Area \[=\frac{16}{3}{{\alpha }^{2}}=48\Rightarrow \alpha =3\]             


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