JEE Main & Advanced
Sample Paper
JEE Main Sample Paper-28
question_answer
If the area bounded by the parabolas \[{{y}^{2}}=4\alpha (x+\alpha )\] and \[{{y}^{2}}=-4\alpha (x-\alpha )\], where \[\alpha >0\] is 48 square units then \[\alpha \] is equal to
A) \[\frac{1}{3}\]
B) \[\frac{1}{9}\]
C) 3
D) 9
Correct Answer:
C
Solution :
Area \[=\frac{16}{3}{{\alpha }^{2}}=48\Rightarrow \alpha =3\]