A) 1
B) 3
C) 5
D) 2
Correct Answer: A
Solution :
Let \[\frac{{{z}_{2}}}{{{z}_{1}}}=i\lambda \] \[\left| \frac{2{{z}_{1}}+3{{z}_{2}}}{2{{z}_{1}}-3{{z}_{2}}} \right|=\left| \frac{2+3i{{\lambda }_{2}}}{2-3i{{\lambda }_{2}}} \right|=1\]You need to login to perform this action.
You will be redirected in
3 sec