A) 9
B) 8
C) 4
D) 2
Correct Answer: D
Solution :
\[e_{1}^{2}=1-\frac{2}{3}=\frac{1}{3}\Rightarrow {{e}_{1}}=\frac{1}{\sqrt{3}}\] As \[{{e}_{1}}{{e}_{2}}=\frac{1}{2}\Rightarrow {{e}_{2}}=\frac{\sqrt{3}}{2}\] Now, \[\frac{3}{4}=1-\frac{{{b}^{2}}}{16}\Rightarrow b=2\]You need to login to perform this action.
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