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JEE Main & Advanced Sample Paper JEE Main Sample Paper-28

  • question_answer
    In a new system of units and 1 unit mass is 9 kg, 1 unit length is 2 m, 1 unit time is 3 sec and 1 unit work is \[x\] Joule then value of \['x'\] will be :

    A)  4                                            

    B)  2

    C)  18                                         

    D)  6

    Correct Answer: A

    Solution :

    \[[W]=M{{L}^{2}}{{T}^{-2}}\] In new system: 1 unit work \[=\frac{(1unit\,\,mass){{(1unit\,\,length)}^{2}}}{{{(1unit\,\,time)}^{2}}}\] \[=\frac{9kg{{(2m)}^{2}}}{{{(3\sec )}^{2}}}=4\frac{kg{{m}^{2}}}{{{\sec }^{2}}}=4J\]


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