A) 200
B) 100
C) \[100\sqrt{2}\]
D) 283
Correct Answer: B
Solution :
The wave form after half wave rectification is shown in figure The rms value of voltage is given by: \[\sqrt{V_{rms}^{2}}=\sqrt{\frac{1}{T}\int_{0}^{T}{{{V}^{2}}dt}}=\] \[=\sqrt{\frac{1}{T}\left[ \int_{0}^{T/2}{V_{0}^{2}}\sin \omega tdt+\int_{T/2}^{T}{0dt} \right]}\] \[=\frac{V_{0}^{2}}{4}\] \[{{V}_{rms}}=\frac{{{V}_{0}}}{2}=\frac{200}{2}=100\,\,W\]You need to login to perform this action.
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