A) \[1.8\times {{10}^{-19}}\]
B) \[5.55\times {{10}^{-10}}\]
C) \[5.55\times {{10}^{-5}}\]
D) \[1.8\times {{10}^{-5}}\]
Correct Answer: B
Solution :
Hydrolysis of \[N{{H}_{4}}Cl\] is written as \[NH_{4}^{+}+{{H}_{2}}ON{{H}_{4}}OH+{{H}^{+}}\] \[\Rightarrow {{K}_{h}}=\frac{{{K}_{w}}}{{{K}_{b}}}\] \[{{K}_{h}}=\frac{{{10}^{-14}}}{1.8\times {{10}^{-5}}}=0.5\times {{10}^{-9}}=5.5\times {{10}^{-10}}\]You need to login to perform this action.
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