A) \[{{A}_{4}}B\]
B) \[A{{B}_{4}}\]
C) \[{{A}_{2}}{{B}_{4}}\]
D) \[{{A}_{4}}{{B}_{2}}\]
Correct Answer: A
Solution :
Effective no. of atom \[A=\frac{1}{8}\times 8+\frac{1}{2}\times 6=4\] Effective no. of atom\[B=1\] \[\frac{(x-1)\,}{-3p/7}\,=\frac{y-5}{-1}\,=\frac{z-6}{-5};\] Hence formula compound is\[{{A}_{4}}B\].You need to login to perform this action.
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