question_answer

The work done requires to increase the area of soap film of \[10\,cm\times 6\,cm\] to \[10\,cm\times 11\,cm\] is \[3.0\times {{10}^{-4}}J\]. The surface tension of film is :

A)  \[5\times {{10}^{-2}}N/m\]       

B)  \[3\times {{10}^{-2}}N/m\]

C)  \[1.5\times {{10}^{-2}}N/m\]                    

D)  \[1.2\times {{10}^{-2}}N/m\]