question_answer

The correct order of hybridisation of central atom in the following species\[N{{H}_{3}},Xe{{O}_{2}},Se{{F}_{4}},N{{O}_{2}}^{+}\]

A)  \[s{{p}^{2}},s{{p}^{3}},s{{p}^{3}}d,sp\]   

B)  \[s{{p}^{3}},s{{p}^{3}}d,s{{p}^{3}}d,sp\]

C)  \[s{{p}^{3}},s{{p}^{3}}{{d}^{2}},s{{p}^{3}}d,s{{p}^{2}}\]

D)  \[s{{p}^{2}},s{{p}^{3}}d,s{{p}^{3}}{{d}^{2}},s{{p}^{2}}\]

Correct Answer: B

Solution :

H.B. \[=\sigma \]bond + lone pair \[=3\sigma +1=4(s{{p}^{3}})\] H.B.\[=\sigma \]bond + lone pair\[=4\sigma +1=5(s{{p}^{3}}d)\] H.B. \[c=\frac{a}{m}\]bond + lone pair\[y=mx+c\] H.B. \[=\sigma \]bond + lone pair \[=2\sigma +1=2(sp)\]