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JEE Main & Advanced Sample Paper JEE Main Sample Paper-28

  • question_answer
    Ionisation energy and electron affinity of fluorine are respectively \[17.42\,eV\] and \[3.45\,\,eV\], then electronegativity of F atom on pauling scale will be

    A)  \[10.44\]                                            

    B)  \[4.0\]

    C)  \[3.72\]                              

    D)  \[2.92\]

    Correct Answer: C

    Solution :

    According to Pauling scale, \[EN=\frac{I.E.+E.A.}{5.6}=\frac{17.42+3.42}{5.6}=3.72eV\]


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