2. Sample Papers
  3. JEE Main & Advanced

JEE Main & Advanced Sample Paper JEE Main Sample Paper-28

  • question_answer
    A mixture of 32 g of \[{{O}_{2}}\] gas and \[8g\,{{D}_{2}}\] gas is allowed to effuse through an orifice, the relative rate of effusion \[\left( \frac{{{r}_{{{D}_{2}}}}}{{{r}_{{{O}_{2}}}}} \right)\] at the start of effusion is

    A)  \[2\sqrt{2}\]                                     

    B)  \[4\sqrt{2}\]

    C)  \[\sqrt{2}\]                                       

    D)  \[\frac{1}{\sqrt{2}}\]

    Correct Answer: B

    Solution :

    According the Graham's law of diffusion \[\frac{{{r}_{{{D}_{2}}}}}{{{r}_{{{O}_{2}}}}}=\frac{{{P}_{{{D}_{2}}}}}{{{P}_{{{O}_{2}}}}}\sqrt{\frac{{{M}_{{{O}_{2}}}}}{{{M}_{{{D}_{2}}}}}}\] \[\frac{{{P}_{{{D}_{2}}}}}{{{P}_{{{O}_{2}}}}}=\frac{\frac{8}{4}}{\frac{32}{32}}=2\] \[\frac{{{r}_{{{D}_{2}}}}}{{{r}_{{{O}_{2}}}}}=\frac{{{P}_{{{D}_{2}}}}}{{{P}_{{{O}_{2}}}}}\sqrt{\frac{{{M}_{{{O}_{2}}}}}{{{M}_{{{D}_{2}}}}}}=2\times \sqrt{\frac{32}{4}}\] \[\frac{{{r}_{{{D}_{2}}}}}{{{r}_{{{O}_{2}}}}}=2\times \sqrt{8}=4\sqrt{2}\]


You need to login to perform this action.
You will be redirected in 3 sec spinner