A) 42
B) 34
C) 43
D) 24
Correct Answer: B
Solution :
For each element of set A, there are 3 possibilities i.e., (i) element of B but not element of C (ii) element of C but not element of B (iii) neither element of B nor element of C So, number of ways = 34You need to login to perform this action.
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