is \[{{32}^{o}}\], then that compound by
is
A) \[-{{32}^{o}}\]
B) \[{{16}^{o}}\]
C) \[{{0}^{o}}\]
D) \[+{{32}^{o}}\]
Correct Answer: C
Solution :
This is a Meso form, so optical rotation produced by that compound is zero.
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