A) 5
B) 4
C) 6
D) 2.8
Correct Answer: B
Solution :
\[\frac{6!}{2!}\,=360\,\,\,\,\,\,\,\,\,\,\,\times \times \times \times \times \times 2\] \[g'(x)\,=2f\,(2f(x)\,+2)\times f'(2f(x)\,+2)\,\times 2f'(x)\] \[x=0,\] \[g'(0)\,=2(-1)\,\times 1\times 2\times 1=-4\] \[f(x)\,=\sin ({{\sin }^{-1}}[x])\,=\left\{ \begin{matrix} 0, & 0\le x<1 \\ 1, & 1\le x<\frac{\pi }{2} \\ \end{matrix} \right.\] \[\therefore \,I=\int\limits_{0}^{1}{0\,dx+\int\limits_{1}^{\frac{\pi }{2}}{1dx=0\,+\left( \frac{\pi }{2}+1 \right)=\frac{\pi -2}{2}}}\]You need to login to perform this action.
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