A) \[4.783\,g/c{{m}^{3}}\]
B) \[4.78\,g/c{{m}^{3}}\]
C) \[4.7\,g/c{{m}^{3}}\]
D) \[4.8\,g/c{{m}^{3}}\]
Correct Answer: D
Solution :
\[2h=a(t_{1}^{2}\,+{{t}_{2}}^{2})\] Since least no. of significant figure in m and v is two. Hence d = 4.8 (Using round off)
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