JEE Main & Advanced Sample Paper JEE Main Sample Paper-29

  • question_answer
    A particle changes its velocity from \[6\,m{{s}^{-1}}\] towards east to \[6\,m{{s}^{-1}}\] towards north in 3 second. Then magnitude of its acceleration will be:

    A) 0                             

    B) \[2\,m{{s}^{-1}}\]

    C) \[2\sqrt{2}m{{s}^{-2}}\]   

    D) \[6\sqrt{2}\,m{{s}^{-2}}\]

    Correct Answer: C

    Solution :

    Average ace. \[2(1+k)\,-(k+2)\,(1-k)=0\] \[{{k}^{2}}+3k=0\] \[k=0\]

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