JEE Main & Advanced Sample Paper JEE Main Sample Paper-29

  • question_answer
    Two bodies of mass 'm' and 9 m are placed at distance r. The gravitational potential at a point on the line joining them where the gravitational field is zero is:

    A) zero                                      

    B) \[\frac{-16Gm}{r}\]

    C) \[\frac{-16Gm}{3r}\]      

    D) \[\frac{-3Gm}{16r}\]

    Correct Answer: C

    Solution :

    \[-{{e}^{-2x}}\,=t\Rightarrow \,\frac{dt}{dy}+\frac{2t}{y}=\frac{2}{{{y}^{3}}}\] \[\therefore \,\,t.{{y}^{2}}\,=\int_{{}}^{{}}{\frac{2}{{{y}^{3}}}.\,{{y}^{2}}dy+C}\] \[\Rightarrow -{{e}^{-2x}}\,.{{y}^{2}}\,=2\ell n\,y\,+C\] \[y(0)=1\] \[\Rightarrow \,C=-1\]

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