JEE Main & Advanced Sample Paper JEE Main Sample Paper-29

  • question_answer
    If three tuning forks of frequencies \[500,\,501\] and \[502\,\,Hz\] are sounded together then the number of beats produced per second will be :

    A) 2                                             

    B) 3

    C) 1              

    D) 0

    Correct Answer: C

    Solution :

    Frequency of beats \[\frac{9}{4}{{m}^{4}}=\frac{9}{2}\,{{m}^{2}}-\frac{9}{4}\Rightarrow \,{{m}^{4}}\,=2{{m}^{2}}-1\]


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