A) \[6-2\pi \]
B) \[2\pi -6\]
C) \[\pi -3\]
D) \[3-\pi \]
Correct Answer: A
Solution :
\[{{\sin }^{-1}}(\sin 14)=(14-4\pi )\] So,\[{{x}^{2}}+3|x|-4=4\pi +(14-4\pi )\] \[\Rightarrow \]\[{{x}^{2}}+3|x|-18=0\] \[\Rightarrow \]\[(|x|+6)(|x|-3)=0\] \[\therefore \,\,|x|\,\,=3\] \[{{\sin }^{-1}}(\sin 2|x|)={{\sin }^{-1}}(\sin 6)=(6-2\pi )\]You need to login to perform this action.
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