A) \[6\,\,J\]
B) \[4\,\,J\]
C) \[5\,\,J\]
D) data insufficient
Correct Answer: A
Solution :
\[x=\frac{-1}{8}\] \[f\left( \frac{-1}{8} \right)\,=\frac{-1}{4}\] \[\frac{dx}{dy}\,=\frac{{{e}^{2x}}+{{y}^{2}}}{{{y}^{3}}}\,\Rightarrow {{e}^{-2x}}\,\frac{dx}{dy}=\frac{1}{{{y}^{3}}}\,+\frac{1}{y\,}{{e}^{-2x}}\]You need to login to perform this action.
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