A) \[y=x+\sqrt{3}\]
B) \[\sqrt{3}y=x-\sqrt{3}\]
C) \[y=\sqrt{3}x-\sqrt{3}\]
D) \[\sqrt{3}y=x-1\]
Correct Answer: B
Solution :
We have, \[(\theta +\theta +{{90}^{o}}-\theta )={{150}^{o}}\Rightarrow \theta ={{60}^{o}}\] \[\Rightarrow \]Slope of line containing reflected ray \[\tan ({{90}^{o}}-{{60}^{o}})=\tan {{30}^{o}}=\frac{1}{\sqrt{3}}\] So, its equation is \[(y-0)=\frac{1}{\sqrt{3}}(x-\sqrt{3})\] \[\Rightarrow \sqrt{3}y=x-\sqrt{3}\]
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