A) \[\frac{3}{8}\]
B) \[\frac{-8}{3}\]
C) \[\frac{-3}{8}\]
D) \[\frac{8}{3}\]
Correct Answer: B
Solution :
\[\frac{dy}{dx}=1+\frac{1}{{{x}^{2}}}\Rightarrow f(x)=x-\frac{1}{x}+\lambda \] \[\Rightarrow \] \[0=1-\frac{1}{1}+\lambda \Rightarrow \lambda =0\] So, \[f(x)=x-\frac{1}{x}\] \[\Rightarrow \]\[f(-3)=-3-\frac{1}{(-3)}=\frac{-3+1}{3}=\frac{-8}{3}\]You need to login to perform this action.
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