A) \[\frac{-1}{2}\]
B) \[\frac{1}{4}\]
C) \[0\]
D) non-existent in the interval
Correct Answer: C
Solution :
Cleary, Rolle's Theorem is applicable for the function \[f(x)\] is\[[-1,\,\,1]\]. Also, \[f'(0)=\underset{h\to 0}{\mathop{lim}}\,\frac{{{h}^{2}}\cos \left( \frac{1}{h} \right)-0}{h}=0\] \[\therefore c=0\]You need to login to perform this action.
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